2025 WAEC GCE Physics likely Questions and Answers

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2025 WAEC GCE Physics likely Questions and Answers

If you’re preparing for the upcoming WAEC GCE examination, this guide on 2025 WAEC GCE Physics likely questions and answers will help you pass with confidence. The 22025 WAEC GCE Physics likely questions and answers were carefully compiled based on the latest WAEC GCE syllabus and previous exam patterns.

By studying this 2025 WAEC GCE Physics likely questions and answers, you’ll understand the most frequently repeated topics and how to approach each question type in both Paper 1 (Objective) and Paper 2 (Theory).

2025 WAEC GCE Physics likely Questions and Answers

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1) Which of the following velocity-time graphs does not
represent an accelerated motion?

Solution
For Options B – D, v is not constant with time.
For Options A, v is constant with time.
Thus option A is correct

2) A car starts from rest and accelerates uniformly for 5s, until it attains a velocity of 30ms–1. It then travels with uniform velocity for 15s before decelerating uniformly to rest in 10s.

(i) Sketch the graph of the motion
(ii) Using the graph in c(i) above calculate the

I) acceleration during the first 5s.
II) deceleration during the last 10s,
III) total distance covered throughout the motion.

(ii) I. Acceleration during the first 5s = gradient of line OA

Gradient of OA = 30 / 5 = 6 units

Therefore, during the first 5s, a = 6ms⁻²

II. Deceleration during the last 10s is the gradient of line BC

Gradient of BC = 30 / (30 – 20) = 30 / 10 = 3 units

Therefore, during the last 10s, Deceleration = 3ms⁻²

III. Total distance covered throughout the motion = Area of Trapezium OABC

= (1/2) * [30 + (20 – 5)] * 30

= (1/2) * (30 + 15) * 30

= (1/2) * 45 * 30

= 15 * 45 = 675 units

Therefore, distance = 675m

3) Name the four physical quantities that are associated with the equations of linear motion

Solution
The quantities are:
(i) displacement (s)
(ii) velocity (v)
(iii) acceleration (a)
(iv) time (t)
Note that for (i) we did not mention distance and for (ii) we didnot mention speed. This is because the motion is linear.

Displacement and velocity are vectors.

4) An object of mass 4kg moves with a uniform velocity of 20ms–1. Calculate the magnitude of its acceleration after 10s.

A 200ms–2

B 25ms–2

C 20ms–2 D 8ms–2

E 0ms–2

Solution
Since we are told that the object moves with uniform
velocity then its acceleration = 0 ( E )

A body starts from rest and accelerates uniformly at 5ms–2.
Calculate the time taken by the body to cover a distance
of 1km.
A 0.63s B 6.32s C 14.14s D 20.00s
Solution
u = 0 ; a = 5ms–2 ; t = ? ; s = 1km = 1000m
The equation of motion that applies here is
s = ut + 1
2
at2
1000 = 0 × t + 1
2
×5 × t2
1000 = 5
2
t2

t2 = 2  1000
5

t = √2 × 1000
5

t = √400 = 20.00s (

5) An object is projected into the air with a speed of 50ms⁻¹ at an angle 30° above the ground level. Calculate the maximum height attained by the object [g = 10ms⁻²]

Solution

Given: