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2026 JAMB Chemistry likely Questions and Answers PDF Download with details explanations 2026 JAMB Chemistry likely Questions and Answers PDF Download Preparing for the 2026 JAMB Chemistry examination requires smart study strategies, and one of the most effective methods is practicing 2026 JAMB Chemistry likely questions and answers. Chemistry is a core science subject in UTME, and many questions are repeated or slightly modified from previous years. In this post, you will find 2026 JAMB Chemistry likely questions and answers, well-explained solutions, exam tips, and a free downloadable PDF to help you score high in your UTME. 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Phone / WhatsApp Number +2349061221656, +2348062853040 Email admin@macoach.com.ng Question 1Question: Given that the difference in electronegativity of elements X and Y is 2.2, the bond that will be formed between them is(a) polar covalent(b) ionic(c) non-polar covalent(d) coordinateTopic: Chemical BondingCorrect Option: (b)Detailed Explanation: The type of chemical bond formed is determined by the difference in electronegativity values between the combining atoms.Difference 1.7: Ionic (Electrovalent).Since 2.2 is greater than 1.7, the bond is ionic.Question 2Question: The radiation used in studying the arrangement of particles in giant organic molecules is(a) βbetaβ-particles(b) γgammaγ-rays(c) αalphaα-particles(d) X-rays Topic: Analytical Chemistry / CrystallographyCorrect Option: (d)Detailed Explanation: X-ray crystallography is the standard technique used to determine the atomic and molecular structure of a crystal. By analyzing the diffraction patterns produced when X-rays pass through the crystal, scientists can deduce the arrangement of particles in giant molecules (like DNA or proteins).Question 3Question: i. CaCO3CaCO_3CaCO3 ii. Ca(HCO3)2Ca(HCO_3)_2Ca(HCO3)2 iii. CaSO4CaSO_4CaSO4. Which of the above causes temporary water hardness if present in water?(a) i only(b) ii only(c) iii only(d) i & ii Topic: Water HardnessCorrect Option: (b)Detailed Explanation:Temporary Hardness is caused by dissolved bicarbonates (hydrogentrioxocarbonate(IV)) of calcium and magnesium, specifically Ca(HCO3)2Ca(HCO_3)_2Ca(HCO3)2 . It can be removed by boiling. Permanent Hardness is caused by sulfates (CaSO4CaSO_4CaSO4) or chlorides. CaCO3CaCO_3CaCO3 is insoluble and forms the "scale" or precipitate, but the dissolved bicarbonate causes the initial hardness. Question 4Question: The dispersion of a liquid in a liquid medium will give(a) an emulsion(b) a sol(c) an aerosol(d) a fogTopic: ColloidsCorrect Option: (a)Detailed Explanation: A colloid where both the dispersed phase and the dispersion medium are liquids is called an emulsion. Examples include milk and mayonnaise.Question 5Question: The respective basicities of HNO3,HCl,CH3COOHHNO_3, HCl, CH_3COOHHNO3,HCl,CH3COOH and H2SO4H_2SO_4H2SO4 are(a) 1, 1, 4 & 2(b) 1, 1, 3 & 2(c) 1, 1, 1 & 2(d) 1, 1, 3 & 1 Topic: Acids, Bases, and SaltsCorrect Option: (c)Detailed Explanation: Basicity is the number of replaceable hydrogen ions (H+H^+H+) in one molecule of an acid. HNO3→H++NO3−HNO_3 rightarrow H^+ + NO_3^-HNO3→H++NO3− (Basicity = 1) HCl→H++Cl−HCl rightarrow H^+ + Cl^-HCl→H++Cl− (Basicity = 1) CH3COOH→H++CH3COO−CH_3COOH rightarrow H^+ + CH_3COO^-CH3COOH→H++CH3COO− (Organic acid, only the carboxyl H is replaceable. Basicity = 1) H2SO4→2H++SO42−H_2SO_4 rightarrow 2H^+ + SO_4^{2-}H2SO4→2H++SO42− (Basicity = 2) Question 6Question:C(s)+H2O(g)→CO(g)+H2(g)C(s) + H_2O(g) rightarrow CO(g) + H_2(g)C(s)+H2O(g)→CO(g)+H2(g). The oxidizing agent in the reaction above is(a) COCOCO(b) H2H_2H2(c) H2OH_2OH2O(d) CCC Topic: Redox ReactionsCorrect Option: (c)Detailed Explanation:Oxidation state of C changes from 0 to +2 (Oxidation).Oxidation state of H in H2OH_2OH2O changes from +1 to 0 (Reduction). The substance that is reduced serves as the oxidizing agent. Therefore, H2OH_2OH2O is the oxidizing agent. Question 7Question: How many coulombs of electricity will be needed to deposit 22.22g of silver?(a) 20212.3C(b) 14189C(c) 25719C(d) 19854CTopic: ElectrolysisCorrect Option: (d)Detailed Explanation:Reaction: Ag++e−→AgAg^+ + e^- rightarrow AgAg++e−→Ag 1 Mole of electrons (1 Faraday = 96500 C) deposits 1 Mole of Ag (108g).Formula: Q=mass×96500Molar MassQ = frac{text{mass} times 96500}{text{Molar Mass}}Q=Molar Massmass×96500 Q=22.22×96500108Q = frac{22.22 times 96500}{108}Q=10822.22×96500 Q≈19853.9CQ approx 19853.9CQ≈19853.9C, which rounds to 19854C. Question 8Question: A compound that gives a brick-red colour to a non-luminous flame is likely to contain(a) Al3+Al^{3+}Al3+(b) Na+Na^+Na+(c) Ca2+Ca^{2+}Ca2+(d) Cu2+Cu^{2+}Cu2+ Topic: Qualitative Analysis (Flame Test)Correct Option: (c)Detailed Explanation: Na+Na^+Na+ gives a Golden Yellow flame. Cu2+Cu^{2+}Cu2+ gives a Blue-Green flame. Ca2+Ca^{2+}Ca2+ gives a Brick-Red flame. Question 9Question: The general formula of haloalkanes where X represents the halide is(a) CnH2n−1XC_nH_{2n-1}XCnH2n−1X(b) CnH2n+1XC_nH_{2n+1}XCnH2n+1X(c) CnH2n−2XC_nH_{2n-2}XCnH2n−2X(d) CnH2nXC_nH_{2n}XCnH2nX Topic: Organic ChemistryCorrect Option: (b)Detailed Explanation: Alkanes have the general formula CnH2n+2C_nH_{2n+2}CnH2n+2. To form a haloalkane (alkyl halide), one hydrogen atom is replaced by a halogen atom (XXX). CnH2n+2→C_nH_{2n+2} rightarrowCnH2n+2→ Remove H →CnH2n+1→rightarrow C_nH_{2n+1} rightarrow→CnH2n+1→ Add X →rightarrow→CnH2n+1XC_nH_{2n+1}XCnH2n+1X. Question 10Question: Which of the following is generated when ethyne is passed through a hot tube containing organo-nickel catalyst?(a) Benzene(b) Polythene(c) Butyne(d) PhenolTopic: Organic Chemistry (Polymerization)Correct Option: (a)Detailed Explanation: This is a polymerization reaction (specifically cyclic polymerization). When Ethyne (C2H2C_2H_2C2H2) is passed through a hot tube with a catalyst, three molecules combine to form Benzene (C6H6C_6H_6C6H6). 3C2H2→C6H63C_2H_2 rightarrow C_6H_63C2H2→C6H6 Question 11Question: The petroleum fraction in industries is in heating furnaces in industries is(a) diesel oil(b) kerosene(c) petrol(d) noneTopic: Industrial Chemistry (Petroleum)Correct Option: (a)Detailed Explanation: While heavy fuel oils are often used for large furnaces, in the context of these options and standard WAEC/JAMB curriculum, Diesel oil (or Gas oil) is the fraction heavier than kerosene and petrol used for heating systems and industrial engines/furnaces.Question 12Question: What is the molar mass of a gas if 2.0g of the gas occupies a volume of 400cm3400cm^3400cm3 at stp?(a) 28gmol−128gmol^{-1}28gmol−1(b) 14gmol−114gmol^{-1}14gmol−1(c) 56gmol−156gmol^{-1}56gmol−1(d) 112gmol−1112gmol^{-1}112gmol−1 Topic: Stoichiometry (Gas Laws)Correct Option: (d)Detailed Explanation:At STP, 1 mole of gas occupies 22,400cm322,400 cm^322,400cm3. If 400cm3400 cm^3400cm3 weighs 2.0g, we need to find the weight of 22,400cm322,400 cm^322,400cm3. Molar Mass=2.0g400cm3×22400cm3text{Molar Mass} = frac{2.0g}{400cm^3} times 22400cm^3Molar Mass=400cm32.0g×22400cm3 Molar Mass=0.005×22400=112gmol−1text{Molar Mass} = 0.005 times 22400 = 112 gmol^{-1}Molar Mass=0.005×22400=112gmol−1. Question 13Question: The following factors have no effect on the value of the equilibrium constant except(a) temperature(b) pressure(c) concentration(d) none of the aboveTopic: Chemical EquilibriumCorrect Option: (a)Detailed Explanation: The equilibrium constant (KcK_cKc or KpK_pKp) is a constant value for a specific reaction at a specific temperature. Changing concentration or pressure shifts the position of equilibrium to maintain the constant, but does not change the constant itself. Only a change in temperature changes the actual value of the equilibrium constant. Question 14Question: What volume of CO produced by reacting excess carbon with 5dm35dm^35dm3 of oxygen?(a) 5dm35dm^35dm3(b) 8dm38dm^38dm3(c) 10dm310dm^310dm3(d) 2.5dm32.5dm^32.5dm3 Topic: StoichiometryCorrect Option: (c)Detailed Explanation:Reaction: 2C(s)+O2(g)→2CO(g)2C(s) + O_2(g) rightarrow 2CO(g)2C(s)+O2(g)→2CO(g) According to Gay-Lussac's law, the ratio of volumes of gases corresponds to the stoichiometric coefficients.Ratio O2:COO_2 : COO2:CO is 1:21 : 21:2. Volume CO=2×Volume O2=2×5dm3=10dm3CO = 2 times text{Volume } O_2 = 2 times 5dm^3 = 10dm^3CO=2×Volume O2=2×5dm3=10dm3. Question 15Question: The shape of the carbon (iv) oxide molecule is(a) tetrahedral(b) angular(c) linear(d) pyramidalTopic: Chemical Bonding (VSEPR)Correct Option: (c)Detailed Explanation: Carbon dioxide (CO2CO_2CO2) has double bonds between the central Carbon and the Oxygen atoms (O=C=OO=C=OO=C=O). There are no lone pairs on the central carbon atom. According to VSEPR theory, this results in a linear shape with a bond angle of 180∘180^circ180∘. Question 16Question: What type of bond can be formed between two elements with electronic structures 1s22s22p41s^22s^22p^41s22s22p4 and 1s22s22p21s^22s^22p^21s22s22p2?(a) ionic(b) metallic(c) covalent(d) dative Topic: Chemical BondingCorrect Option: (c)Detailed Explanation:Element 1 (1s22s22p41s^22s^22p^41s22s22p4) has 8 electrons total (Oxygen, Group 6). It is a non-metal. Element 2 (1s22s22p21s^22s^22p^21s22s22p2) has 6 electrons total (Carbon, Group 4). It is a non-metal. Bonds formed between two non-metals are covalent (sharing of electrons).Question 17Question: When water is added to anhydrous CoCl2CoCl_2CoCl2, the colour changes from(a) white to blue(b) blue to white(c) blue to pink(d) pink to white Topic: Transition MetalsCorrect Option: (c)Detailed Explanation: Cobalt(II) chloride serves as a test for water.Anhydrous CoCl2CoCl_2CoCl2 is Blue. Hydrated CoCl2⋅6H2OCoCl_2 cdot 6H_2OCoCl2⋅6H2O is Pink. Therefore, adding water changes it from Blue to Pink.Question 18Question: The following are salts except(a) zinc nitrate(b) sodium carbonate(c) calcium oxide(d) magnesium chlorideTopic: Acids, Bases, and SaltsCorrect Option: (c)Detailed Explanation:Zinc nitrate, Sodium carbonate, and Magnesium chloride are all salts (products of acid-base neutralization).Calcium oxide (CaOCaOCaO) is a metal oxide, which acts as a Base (specifically a basic oxide), not a salt. Question 19Question: In an electrochemical cell, polarization is caused by(a) oxygen(b) hydrogen(c) chlorine(d) tetraoxosulphate(vi)acidTopic: ElectrochemistryCorrect Option: (b)Detailed Explanation: Polarization occurs in simple cells when Hydrogen gas bubbles accumulate around the copper anode (positive electrode). This insulates the electrode and sets up a back electromotive force, stopping the current flow.Question 20Question: A metal that forms soluble trioxosulphate(iv) salt is(a) manganese(b) aluminum(c) barium(d) potassiumTopic: Solubility RulesCorrect Option: (d)Detailed Explanation: Trioxosulphate(IV) salts are Sulfites (SO32−SO_3^{2-}SO32−). Most sulfites are insoluble in water, except for those of Alkali metals (Group 1) and Ammonium. Potassium is a Group 1 alkali metal, so K2SO3K_2SO_3K2SO3 is soluble. Question 21Question: 2-methylpropan-2-ol is a/an _______ alkanol(a) primary(b) secondary(c) tertiary(d) incombustibleTopic: Organic Chemistry (Alcohols)Correct Option: (c)Detailed Explanation:Structure: The Carbon holding the OH group is bonded to three other methyl groups (CH3CH_3CH3). CH3−C(CH3)(OH)−CH3CH_3 - C(CH_3)(OH) - CH_3CH3−C(CH3)(OH)−CH3. Since the carbon with the OH is attached to 3 other carbons, it is a tertiary alkanol.Question 22Question: The decarboxylation of ethanoic acid will produce(a) CO2CO_2CO2 and methane(b) CO2CO_2CO2 and ethane(c) COCOCO and methane(d) COCOCO and ethane Topic: Organic ChemistryCorrect Option: (a)Detailed Explanation: Decarboxylation involves the removal of a carboxyl group (−COOH-COOH−COOH), usually in the form of Carbon dioxide (CO2CO_2CO2). CH3COOH→CH4+CO2CH_3COOH rightarrow CH_4 + CO_2CH3COOH→CH4+CO2 This produces Methane and Carbon dioxide. (Note: In laboratory preparation using soda lime, the CO2CO_2CO2 is trapped as carbonate, but the chemical breakdown products are methane and carbon dioxide). Question 23Question: Which of the following qualifies elements in the same period?(a) equal number of valence electrons(b) equal number of shell(c) equal number of neutrons(d) equal nuclear energyTopic: Periodic TableCorrect Option: (b)Detailed Explanation: Elements in the same period (horizontal row) have the same number of electron shells (energy levels). Elements in the same Group have the same number of valence electrons.Question 24Question: A substance is said to be impure if(a) it is coloured(b) it has a low melting point(c) its melting point range is wide(d) it is insoluble in waterTopic: Separation Techniques / PurityCorrect Option: (c)Detailed Explanation: Pure substances have sharp, specific melting points. Impurities interfere with the crystal lattice structure, causing the substance to melt over a wide range of temperatures and usually at a lower temperature than the pure substance.Question 25Question: How many isomers does C3H6Cl2C_3H_6Cl_2C3H6Cl2 have?(a) 2(b) 3(c) 4(d) 5 Topic: Organic Chemistry (Isomerism)Correct Option: (c)Detailed Explanation: The structural isomers are:1,1-dichloropropane1,2-dichloropropane1,3-dichloropropane2,2-dichloropropaneThere are 4 structural isomers.Question 26Question: Which of the following is non-biodegradable?(a) wood(b) plastic(c) paper(d) faecesTopic: Environmental ChemistryCorrect Option: (b)Detailed Explanation: Biodegradable materials can be broken down by bacteria and other microorganisms. Wood, paper, and faeces are organic and biodegradable. Plastic is synthetic and resistant to biological decomposition.Question 27Question: Which of the following is a fine chemical?(a) Caustic soda(b) sulphuric acid(c) dyes(d) noneTopic: Industrial ChemistryCorrect Option: (c)Detailed Explanation:Heavy chemicals (e.g., Sulphuric acid, Caustic soda) are produced in huge quantities with a focus on bulk and low cost.Fine chemicals (e.g., Dyes, Drugs, Additives) are produced in smaller quantities with a high degree of purity and specificity.Question 28Question: How many unpaired electrons are in the p-orbitals of an oxygen atom?(a) 0(b) 1(c) 2(d) 3Topic: Atomic StructureCorrect Option: (c)Detailed Explanation:Oxygen atomic number is 8. Configuration: 1s22s22p41s^2 2s^2 2p^41s22s22p4. The p-subshell has 3 orbitals. According to Hund's rule, electrons fill singly first.Fill 4 electrons: [↑↓uparrowdownarrow↑↓] [↑uparrow↑] [↑uparrow↑]. There are 2 unpaired electrons.Question 29Question: The radioactive emission with the least ionization power is(a) alpha particles(b) beta particles(c) gamma rays(d) X-raysTopic: Nuclear ChemistryCorrect Option: (c)Detailed Explanation:Alpha particles: Highest mass/charge, Highest ionization, Lowest penetration.Gamma rays: No mass/charge, Lowest ionization, Highest penetration.Question 30Question: How many atoms are present n 48g of magnesium?(a) 6.02×10236.02 times 10^{23}6.02×1023(b) 1.204×10241.204 times 10^{24}1.204×1024(c) 3.01×10233.01 times 10^{23}3.01×1023(d) 1.51×10241.51 times 10^{24}1.51×1024 Topic: Mole ConceptCorrect Option: (b)Detailed Explanation:Molar mass of Mg = 24 g/mol .Moles = 4824=2frac{48}{24} = 22448=2 moles. Atoms = Moles ×times× Avogadro's Constant (6.02×10236.02 times 10^{23}6.02×1023). 2×6.02×1023=12.04×1023=1.204×10242 times 6.02 times 10^{23} = 12.04 times 10^{23} = mathbf{1.204 times 10^{24}}2×6.02×1023=12.04×1023=1.204×1024. Question 31Question:50cm350cm^350cm3 of gas was collected over water at 10∘C10^circ C10∘C and 765mmHg765mmHg765mmHg. Calculate the volume of the gas at s.t.p if the saturated vapour pressure of water at 10∘C10^circ C10∘C is 5mmHg5mmHg5mmHg.(a) 48.55cm348.55cm^348.55cm3(b) 48.23cm348.23cm^348.23cm3(c) 49.19cm349.19cm^349.19cm3(d) 50.59cm350.59cm^350.59cm3 Topic: Gas LawsCorrect Option: (b)Detailed Explanation: Pgas=Ptotal−SVP water=765−5=760mmHgP_{text{gas}} = P_{text{total}} - text{SVP water} = 765 - 5 = 760text{mmHg}Pgas=Ptotal−SVP water=765−5=760mmHg. V1=50cm3V_1 = 50cm^3V1=50cm3, T1=10+273=283KT_1 = 10 + 273 = 283KT1=10+273=283K. STP conditions: P2=760mmHgP_2 = 760text{mmHg}P2=760mmHg, T2=273KT_2 = 273KT2=273K. Using P1V1T1=P2V2T2frac{P_1V_1}{T_1} = frac{P_2V_2}{T_2}T1P1V1=T2P2V2: 760×50283=760×V2273frac{760 times 50}{283} = frac{760 times V_2}{273}283760×50=273760×V2 Cancel 760 from both sides: 50283=V2273frac{50}{283} = frac{V_2}{273}28350=273V2 V2=50×273283≈48.23cm3V_2 = 50 times frac{273}{283} approx 48.23cm^3V2=50×283273≈48.23cm3. Question 32Question: Group VII elements are(a) electron donors(b) monoatomic(c) good oxidizing agent(d) highly electropositiveTopic: Periodic Table (Halogens)Correct Option: (c)Detailed Explanation: Group VII elements (Halogens) have 7 valence electrons. They readily accept one electron to complete their octet. This ability to accept electrons makes them strong oxidizing agents. (They are electronegative, not electropositive).Question 33Question: Which of the following gases has a pungent smell, turns red litmus paper blue and forms white dense fumes with hydrogen chloride gas?(a) NH3NH_3NH3(b) NO2NO_2NO2(c) N2N_2N2(d) Cl2Cl_2Cl2 Topic: Qualitative Analysis (Gases)Correct Option: (a)Detailed Explanation:Pungent smell + Turns Red Litmus Blue (Basic) = Ammonia (NH3NH_3NH3). Reaction with HCl: NH3(g)+HCl(g)→NH4Cl(s)NH_3(g) + HCl(g) rightarrow NH_4Cl(s)NH3(g)+HCl(g)→NH4Cl(s) (White Fumes). Question 34Question: An example of oxidation-reduction enzyme is(a) lipase(b) dehydrogenase(c) amylase(d) proteaseTopic: BiochemistryCorrect Option: (b)Detailed Explanation:Lipase, Amylase, and Protease are hydrolases (break bonds with water).Dehydrogenase enzymes facilitate the removal of hydrogen atoms, which is an oxidation reaction (Redox).Question 35Question: A metal X forms two types of chlorides, XCl2XCl_2XCl2 and XCl3XCl_3XCl3. This illustrates the law of(a) constant composition(b) multiple proportion(c) reciprocal proportion(d) definite proportion Topic: Laws of StoichiometryCorrect Option: (b)Detailed Explanation: The Law of Multiple Proportions states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in a ratio of small whole numbers. (Here X combines with Cl in ratios leading to XCl2XCl_2XCl2 and XCl3XCl_3XCl3). Question 36Question: The hydrolysis of NH4ClNH_4ClNH4Cl gives a/an ______ solution(a) neutral(b) acidic(c) basic(d) buffer Topic: Salt HydrolysisCorrect Option: (b)Detailed Explanation:NH4ClNH_4ClNH4Cl is a salt formed from a Strong Acid (HClHClHCl) and a Weak Base (NH3NH_3NH3). Upon hydrolysis, the solution will be Acidic (pH < 7). Question 37Question: Which of the following is used to hasten the ripening of fruit?(a) ethene(b) ethyne(c) ethane(d) acetyleneTopic: Organic ChemistryCorrect Option: (a)Detailed Explanation: Ethene (C2H4C_2H_4C2H4) is a natural plant hormone that triggers the ripening process in fruits. Question 38Question: A solid substance with high melting and boiling points is likely to be a/an(a) covalent compound(b) dative compound(c) ionic compound(d) non-metalTopic: Bonding PropertiesCorrect Option: (c)Detailed Explanation: Ionic compounds consist of a giant lattice structure held together by strong electrostatic forces. This requires a large amount of energy to break, resulting in high melting and boiling points. (While giant covalent structures also have high MPs, "ionic" is the general characteristic answer compared to simple covalent molecules).Question 39Question: The minimum amount of energy required for effective collisions between reacting particles is known as(a) effective energy(b) activation energy(c) bond energy(d) lattice energyTopic: Chemical KineticsCorrect Option: (b)Detailed Explanation: Activation Energy (EaE_aEa) is the minimum energy barrier that reacting particles must overcome for a collision to result in a chemical reaction. Question 40Question: Which of the following metals exists as liquid at ordinary temperature?(a) calcium(b) silver(c) mercury(d) platinumTopic: MetalsCorrect Option: (c)Detailed Explanation: Mercury (Hg) is the only metal that is in the liquid state at standard room temperature and pressure.2026 JAMB Chemistry likely questions and answers, JAMB Chemistry 2026, JAMB Chemistry PDF download, UTME Chemistry questions, JAMB Chemistry past questions, JAMB Chemistry syllabus, Chemistry UTME preparation, JAMB 2026 exam guide Phone / WhatsApp Number +2349061221656, +2348062853040 Email admin@macoach.com.ng Share to: Trending Updates Latest postHidden FactsJAMB Questions and AnswersJAMB UpdatesJob Exam Past Questions & AnswersLesson NoteNECO GCEWAEC GCEWAEC GCE Questions and AnswersWAEC Questions and Answers BackJAMB Past Questions and Answers2026 JAMB English Language Questions and Answers BackDownload Nursery 1 Lesson Note For All SubjectsDownload Nursery 2 Lesson Note for All Subjects BackJAMB Syllabus PDF BackNigerian Customs Service ExamsNigeria NavyNigeria Air Force NAFNigerian Security and Civil Defence CorpsNigerian Custom Services Past Questions and Answers PDFNigeria Navy Past Questions and Answers PDFNigeria Air Force past questions and answers PDF BackNigeria Air Force past questions and answers PDF BackNigeria Navy Past Questions and Answers PDF BackNigerian Custom Services Past Questions and Answers PDF BackNursery School Lesson NoteDownload Nursery 1 Lesson Note For All SubjectsDownload Nursery 2 Lesson Note for All Subjects BackWAEC Past Questions and AnswersWAEC Biology Questions and Answers BackWAEC GCE Mathematics Questions and Answers2026 JAMB Chemistry Likely Questions and Answers2026 JAMB Physics Likely Questions and AnswersWAEC English Language Past Questions and Answers PDF DownloadWAEC Mathematics Past Questions and Answers PDF Download2026 jamb mathematics Questions and Answers2026 JAMB Mathematics Likely Questions and Answers | JAMB Expo 2026 Maths SolutionsWAEC Literature in English Syllabus PDF DownloadWAEC Physics Syllabus PDF DownloadWAEC Chemistry Syllabus PDF DownloadLoad MoreEnd of Content. 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